(window.slotbydup=window.slotbydup || []).push({
id: '2081942',
container: s,
size: '1000,60',
display: 'inlay-fix'通过给出的条件化简变形,找出三角形三边的关系,然后再判断三角形的形状.
;方程两边同除以,因为的值有可能是;或或或或该三角形是直角三角形或等腰三角形.
本题考查了因式分解和公式变形等内容,变形的目的就是找出三角形三边的关系再判定三角形的形状.
3894@@3@@@@勾股定理的逆定理@@@@@@258@@Math@@Junior@@$258@@2@@@@三角形@@@@@@52@@Math@@Junior@@$52@@1@@@@图形的性质@@@@@@7@@Math@@Junior@@$7@@0@@@@初中数学@@@@@@-1@@Math@@Junior@@
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求解答 学习搜索引擎 | 请阅读下列解题过程:已知a,b,c为\Delta ABC的三边,且满足{{a}^{2}}{{c}^{2}}-b+2{{c}^{2}}={{a}^{4}}-{{b}^{4}},试判断\Delta ABC的形状.解:因为{{a}^{2}}{{c}^{2}}-{{b}^{2}}{{c}^{2}}={{a}^{4}}-{{b}^{4}},A所以{{c}^{2}}({{a}^{2}}-{{b}^{2}})=({{a}^{2}}+{{b}^{2}})({{a}^{2}}-{{b}^{2}}),B所以{{c}^{2}}={{a}^{2}}+{{b}^{2}},C所以\Delta ABC为直角三角形.D问:(1)在上述解题过程中,从哪一步开始出现错误:___;(2)错误的原因是:___;(3)本题正确的结论是:___.16^x-9^(x+1)=8*12^x求解题步骤
16^x-9^(x+1)=8*12^x求解题步骤
等式两边同时除以12的x次方，再把(3/4)^x设为t,此时相当于解一元二次不等式。最后得t,再得x.请采纳。
4^2x-9*3^2x=8*(3*4)x=8*3^x*4^x
两边同除以3^x*4^x
4^x/3^x
9*(3^x/4^x)=8
令4^x/3^x=t
即t-9/t=8
同乘t
即t^2-8t-9=0
解之得t=9或
t=-1（舍去）
4^x/3^x=9
即(4/3)^x=9
x=log(4/3)9



其他回答 (2)
等式两边除以9^x得& (16/9)^x-9=8*(12/9)^x =&(4/3)^(2x)-9-8*(4/3)^x=0 把这个等式看成一元二次方程来解。
[(4/3)^x-9]*[*(4/3)^x+1]=0 =&(4/3)^x=9,负数舍去。后面的自己可以解了哦。。。 我下班要回家了，有疑问可以追问，晚点再回你
4^2x-9*3^2x=8*3^x*4^x
(4^x-9*3^x)(4^x+3^x)=0
log(4/3)9=x
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求解答过程：阅读理解。
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在 TAPI.JsonData.op_Explicit(JsonData data)
在 TAPI.Defs.&LoadItems&b__59(JsonData data, String key, Int32& value)
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