已知设集合a x x2 4x 0=x丨x平方+4x+3≥0 B=x丨2的x次方<1 则A交B=

若集合a等于大括号xlx的平方+4x=0大括号,B=大括号xlx的平方+2(a+1)x+a的平方1=0大括号,若B包含于A求实数a的取值范围_百度作业帮 若集合a等于大括号xlx的平方+4x=0大括号,B=大括号xlx的平方+2(a+1)x+a的平方1=0大括号,若B包含于A求实数a的取值范围 787884nwCI1 x^2+4x=0解得x=0,或x=-4∴A={0,-4}B={x|x的平方+2(a+1)x+a的平方-1=0},∵B包含于A,B是A的子集∴B=Φ,或{0},或{-4},或{-4,0}1)若B=Φ, ∴Δ=4(a+1)²-4(a²-1) 其他类似问题 为什么a小于等于-1 扫描下载二维码已知函数f(x)=x的四次方-4x的三次方+ax的平方-1在区间[0,1]上单调递增,在区间[1,2]上单调递减.(1) 若点A(X0 ,f(X0))在函数f(x)的图象上,求证:点A关于直线X=1的对称点B也在函数f(x)的图像上;(2)是_百度作业帮 已知函数f(x)=x的四次方-4x的三次方+ax的平方-1在区间[0,1]上单调递增,在区间[1,2]上单调递减.(1) 若点A(X0 ,f(X0))在函数f(x)的图象上,求证:点A关于直线X=1的对称点B也在函数f(x)的图像上;(2)是否存在实数b使得函数g(x)=x^4+bx^2+1(其中b小于4)的图像与f(x)的图象恰有3个交点,若有,求出实数b的范围,若不存在请说明理由. Hotel government jobs have been professions which have been value your time as well as courtesy.In actuality,for many humans who have been not nonetheless motionless upon a career Manolo Blahnik Brown Carolyne Pumps trail to yield,road house government is a really great choice.Like any alternative contention,road house government requires loyalty,stability,as well as many of all,joining.If we consider we follower of Jesus louboutin all these,road house government competence be a undiluted citation for we.Here have been a little affidavit because it is an choice to investigate road house management:Professional translators have been rarely prepared denunciation professionals who have modernized educational precision in languages and/or in the abstruse theme make the difference.Manolo Blahnik White Suw Sandals It takes most years of indepth studies to turn indeed accomplished in translations.Denunciation is the really biased as well as formidable margin,as well as simple elements of linguistic scholarship such as abbreviation,punctuation as well as spelling usually anatomy the tiny partial of linguistic cunning.Their life often stays a poser to a wow bullion peoples of complicated Azeroth,yet a Earthen Ring has schooled of Azshara's naga abduction Vashj'ir for an different role as a cries of a elements relate opposite Azeroth from a Abyss.Vashj'ir is a turn 78-82 section Manolo Blahnik Black Ebete Sandlas in World of Warcraft:Cataclysm area players will be alleged to try a inlet of a Great Sea as well as stop a naga from abduction infinite energy from a area of Neptulon a Tidehunter.A reception room which provides we with a account of things which could go amiss is a obliged reception room.Though accurate to be comparatively protected there have been still risks concerned with tanning.A reception room should have a anatomy indicating them all out which we pointer only in box something happens.This serves to surprise we,a customer,as well as strengthen a reception room.. 其他类似问题 扫描下载二维码已知关于两个x的代数式A,B,其中A=mx的|m|+4次方+nx的立方-5x的平方+2,B=x的五次方-2x的立方+4x1)是否存在m、n,使得A-B是五次四项式.(2)在(1)的条件下,若m不等于0,定义运算a#(#一种运算_百度作业帮 已知关于两个x的代数式A,B,其中A=mx的|m|+4次方+nx的立方-5x的平方+2,B=x的五次方-2x的立方+4x1)是否存在m、n,使得A-B是五次四项式.(2)在(1)的条件下,若m不等于0,定义运算a#(#一种运算符号)b=ma的平方-nb的平方,求(-2)#3. 1、A-B=mx的|m|+4次方+nx的立方-5x的平方+2-(x的五次方-2x的立方+4x)=mx的|m|+4次方+nx的立方-5x的平方+2-x的五次方+2x的立方-4x=mx的|m|+4次方-x的五次方+(n+2)x的立方-5x的平方-4x+2当m=0,n≠-2时,A-B=-x的五次方+(n+2)x的立方-5x的平方-4x+2 信息中心 > 已知ax的四次方+bx的三次方+cx的二 来源:互联网 发表时间: 6:27:42 责任编辑:鲁晓倩字体: 为了帮助网友解决“已知ax的四次方+bx的三次方+cx的二”相关的问题,中国学网通过互联网对“已知ax的四次方+bx的三次方+cx的二”相关的解决方案进行了整理,用户详细问题包括:RT,我想知道:已知ax的四次方+bx的三次方+cx的二次方+dx+e=(x-2)的四次方(1)当x=1时,求a+b+c+d+e的值;(2)当x=0时,求e的值;(3)当x=-1时,求a-b+c-d+e的值;(4)试求a+c的值。,具体解决方案如下:解决方案1: (x-2)^4=x^4-4x^3*2+6x^2*2^2-4x*2^3+2^4=x^4-8x^3+24x^2-32x+16=ax^4+bx^3+cx^2+dx+e所以a=1;b=-8;c=24;d=-32;e=16(1)当x=1时,ax^4+bx^3+cx^2+dx+e=a+b+c+d+e=(1-2)^4=1(2)当x=0时,ax^4+bx^3+cx^2+dx+e=e=(0-2)^4=16(3)当x=-1时,ax^4+bx^3+cx^2+dx+e=a-b+c-d+e=(-1-2)^4=81(4)a+c=[(a+b+c+d+e)+(a-b+c-d+e)]/2-e=82/2-16=25最简单的方法直接用a,b,c,d,e的值计算解决方案2: (1)等于1(2)等于16(3)等于81(4)等于25& 1个回答1个回答1个回答1个回答1个回答1个回答1个回答1个回答1个回答1个回答1个回答 相关文章: 最新添加资讯 24小时热门资讯 Copyright © 2004- All Rights Reserved. 中国学网 版权所有 京ICP备号-1 京公网安备02号}

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