十二十三十四题求答案!急 _百度作业帮
十二十三十四题求答案!急
十二十三十四题求答案!急&
don't take actionsare waiting forare being built
don't take actionsare there expect meare being built初三数学题求解，第十三题，要求写出具体过程，谢谢！_百度知道
初三数学题求解，第十三题，要求写出具体过程，谢谢！
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太给力了，你的回答完美解决了我的问题！
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解：x+4x-2=0
所3x+12x+2004
=3（x+4x）+2004
所3（x+4x）+2004
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TPO12阅读第一篇第五题
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TPO13 2800多套实战TPO视频讲解由小马托福权威名师录制，阅读原文答案解析，听力解析等,倾情分享！
　　Paragraph 1: We all know that many more people today are right-handed than left-handed. Can one trace this same pattern far back in prehistory? Much of the evidence about right-hand versus left-hand dominance comes from stencils and prints found in rock shelters in Australia and elsewhere, and in many Ice Age caves in France, Spain, and Tasmania. When a left hand has been stenciled, this implies that the artist was right-handed, and vice versa. Even though the paint was often sprayed on by mouth, one can assume that the dominant hand assisted in the operation. One also has to make the assumption that hands were stenciled palm downward—a left hand stenciled palm upward might of course look as if it were a right hand. Of 158 stencils in the French cave of Gargas, 136 have been identified as left, and only 22 right-handedness was therefore heavily predominant.
　　Paragraph 2: Cave art furnishes other types of evidence of this phenomenon. Most engravings, for example, are best lit from the left, as befits the work of right-handed artists, who generally prefer to have the light source on the left so that the shadow of their hand does not fall on the tip of the engraving tool or brush. In the few cases where an Ice Age figure is depicted holding something, it is mostly, though not always, in the right hand.
　　5．All of the following are mentioned in paragraphs 1 and 2 as evidence of right-handedness in art and artists EXCEPT
○ the ideal source of lighting for most engravings
○ the fact that a left hand stenciled palm upward might look like a right hand
○ the prevalence of outlines of left hands
○ figures in prehistoric art holding objects with the right hand○
本篇阅读所有题目视频讲解导航 ↓
玩手机的时候想看TPO讲解就来扫码吧
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考个托福报个班，动辄学费上万，效果就像墙上掉下来的渣渣，收了一地的渣！！捶胸顿足有没有？嘘！别捶啦，不用在懊恼，深呼吸！
用唐老鸭的话说：啊哈哈哈，今天是个好天气；虽然外面烟雾缭绕吧！
但是，小马却可以给考托的童鞋带来一个好心情，特别推出：留学考试会员制！
2015年11月的考试马上就过去啦，12月即将到来。2015年12月总共有5场托福考试，12月考试的同学是不是还在紧张备考中呢？为了帮助同学们更好的备考托福，小马给大家准备了/12/13/19/20日托福机经【抢先预订版】。
日托福机经 开始预订 需要的来下载吧！广大的8月30日考试的考生们，你们注意了，30日的托福机经可以开始预订了，大家可以不和下载，直接扫码加入8月30日机经预定群，马叔直接把机经发送到邮箱，发邮箱！发邮箱！发邮箱！发邮箱！
SSS科学六十秒(六十-second science),,sss只有一分钟，但是语速快，信息量大。最重要的是，常作为托福考试听力出题的重要来源。初听者会觉得这就是在磨耳朵，但同样很多朋友反映听多了SSS之后觉得TPO非常拖节奏，很慢，甚至听到想睡觉。适应了sss的语速，再听托福的语速可以说是慢到让你觉得不耐烦。
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北京小马过河互联网科技有限公司 版权所有高一一道数学题,求解,哥哥姐姐帮帮忙嘛!急啊!已知向量m=(sin1/2,1),n=(4倍根号3倍cosx/2,2cosx)设函数f(x)=m.n
(1)求函数f(x)的解析式.
(2)求函数f(x),x属于[负排,排]的单调递增区间.
(3)设函数h(x)=f_百度作业帮
高一一道数学题,求解,哥哥姐姐帮帮忙嘛!急啊!已知向量m=(sin1/2,1),n=(4倍根号3倍cosx/2,2cosx)设函数f(x)=m.n
(1)求函数f(x)的解析式.
(2)求函数f(x),x属于[负排,排]的单调递增区间.
(3)设函数h(x)=f
高一一道数学题,求解,哥哥姐姐帮帮忙嘛!急啊!已知向量m=(sin1/2,1),n=(4倍根号3倍cosx/2,2cosx)设函数f(x)=m.n
(1)求函数f(x)的解析式.
(2)求函数f(x),x属于[负排,排]的单调递增区间.
(3)设函数h(x)=f(x)-k(k属于R)在区间[负排,排]上的零点个数为n,试探求n的值及对应的k的取值范围.
已知向量m=(sin(x/2),1)；n=(4(√3)cos(x/2),2cosx)；设函数f(x)=m▪n&；(1)求函数f(x)的解析式.& &(2)求函数f(x),x属于[-π,π]的单调递增区间.& &(3)设函数h(x)=f(x)-k(k属于R)在区间[-π,π]上的零点个数为n,试探求n的值及对应的k的取值范围.(1)f(x)=4(√3)sin(x/2)cos(x/2)+2cosx=2(√3)sinx+2cosx=4[(√3/2)sinx+(1/2)cosx]=4[sinxcos(π/6)+cosxsin(π/6)]=4sin(x+π/6).(2).单增区间：由2kπ-π/2≦x+π/6≦2kπ+π/2,得单增区间为：2kπ-2π/3≦x≦2kπ+π/3.(3).h(x)=4sin(x+π/6)-k；在区间[-π,π]上：& & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & & &当k&4或k&-4时h(x)无零点；当k=4或k=-4时各有一个零点；当-2&k&4时h(x)有2个零点；当k=-2时h(x)有3个零点；当-4&k&-2时有2个零点.请看下图：作y=k的水平线于图像交点的个数就是零点的个数.
按照正常思路就可以了啊，1是向量点乘，这个不用说应该会吧，就是对应横坐标纵坐标相乘得数再相加，后面的实在没思路你可以画图试试。解数学题目思路很重要，不用光看结果~
我感觉你把向量m的横坐标打错了！
f(x)=mn=4倍根号3倍cos(x/2)Sin(1/2)+2Cosx
(m向量里是sin1/2还是sinx/2,？？？？)}