扫二维码下载作业帮
拍照搜题，秒出答案，一键查看所有搜题记录
下载作业帮安装包
扫二维码下载作业帮
拍照搜题，秒出答案，一键查看所有搜题记录
高中数学函数题目 在线等答案或中文翻译题目是英文版本的.求题解,需要详细过程.或者是题目的中文翻译,都可以1. Sara was sitting on a swing, talking about the mathematics she had been doing at school and swinging gently to and fro. She noticed that the period of one complete swing was 3 seconds and that if she did nothing to keep going, the amplitude of her motion decreased from 1 metre to 50cm in 2 minutes. If Sara’s horizontal displacement is x metres after t second, find a function of the form x=Ae-ktcos nt to describe this motion. Find an expression for Sara’s horizontal velocity after t seconds.2. Show that the area under the curve y=x2-1/12 from x=r-1/2 to x=r+1/2. By considering the area under this curve from x=1/2 to x=n+1/2, show that :1&sup2;+2&sup2;+3&sup2;+……….+n&sup2;=n(n+1)(2n+1)/63. Suppose that x has density f(x)=12x&sup2;(1-x) for 0<x<1.Is x a density function? Find the mode, median and mean of x. sketch the graph of f and show the location of the mean, median and mode on the x-axis. What is the probability that a randomly selected value from this distribution is between 0.2and 0.4?
扫二维码下载作业帮
拍照搜题，秒出答案，一键查看所有搜题记录
1. Sara was sitting on a swing, talking about the mathematics she had been doing at school and swinging gently to and fro. She noticed that the period of one complete swing was 3 seconds and that if she did nothing to keep going, the amplitude of her motion decreased from 1 metre to 50cm in 2 minutes. If Sara’s horizontal displacement is x metres after t second, find a function of the form x=Ae-ktcos nt to describe this motion. Find an expression for Sara’s horizontal velocity after t seconds.Sara坐在秋千上前后晃着,讨论着在学校做过的数学题.她发现如果她不去晃秋千,那么秋千完成一个周期需要3秒钟时间.秋千摇摆的幅度在两分钟内从1米降到了0.5米.如果Sara的竖直方向高度在t时间时为x.问题：找到一个合适的变量满足x=Ae^(-k)cosnt,来描述这个运动.得到t时刻时Sara的竖直方向上的速度.2. Show that the area under the curve y=x2-1/12 from x=r-1/2 to x=r+1/2. By considering the area under this curve from x=1/2 to x=n+1/2, show that :1&sup2;+2&sup2;+3&sup2;+……….+n&sup2;=n(n+1)(2n+1)/6画出y=x^2-1/12在x=r-1/2到x=r+1/2之间内与x轴围成的图形的面积.通过考虑曲线从x=1/2到x=n+1/2区间的图形面积,证明1^2+2^2+3^2+.+n^2=n(n+1)(2n+1)/63. Suppose that x has density f(x)=12x&sup2;(1-x) for 0<x<1.Is x a density function? Find the mode, median and mean of x. sketch the graph of f and show the location of the mean, median and mode on the x-axis. What is the probability that a randomly selected value from this distribution is between 0.2and 0.4?
证明函数f(x)=12x^2(1-x) 0<x<1 是否是x的密度函数.（就是面积是不是等于1）求x的模,中位数和均值的,并在图中画出.从该分布函数上随机取一个值,那么它落在0.2到0.4之间的概率是多大?
为您推荐：
其他类似问题
1.莎拉坐在秋千上想着她在学校里做过的数学题。秋千慢慢地来回荡来荡去。她注意到：秋千来回荡的完整周期是3秒钟，如果她不用力使秋千运动，她所坐的秋千的振幅会在2分钟内从1m减少为50cm. 假设莎拉t秒后的水平位移为x,找出一个类似于x=Ae-ktcos nt 的函数来描述这种运动。求莎拉t秒后的水平速度。（只看得懂第一题哈）...
扫描下载二维码扫二维码下载作业帮
拍照搜题，秒出答案，一键查看所有搜题记录
下载作业帮安装包
扫二维码下载作业帮
拍照搜题，秒出答案，一键查看所有搜题记录
人教版高中数学必修5课本答案及过程.在线等.急.
这厮TA1143
扫二维码下载作业帮
拍照搜题，秒出答案，一键查看所有搜题记录
去买参考书啊,打字很多的
为您推荐：
其他类似问题
扫描下载二维码学渣在线等，高中数学有那种练习册是都是基础题目的_数学吧_百度贴吧
&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&签到排名：今日本吧第个签到，本吧因你更精彩，明天继续来努力！
本吧签到人数：0成为超级会员，使用一键签到本月漏签0次！成为超级会员，赠送8张补签卡连续签到：天&&累计签到：天超级会员单次开通12个月以上，赠送连续签到卡3张
关注：426,642贴子：
学渣在线等，高中数学有那种练习册是都是基础题目的收藏
唉，高一高二每好好学习 现在想认真学习了 ，求学霸告知 哪种练习册适合我这种基础不好的学渣使用的
翡翠原石:购买、加盟、批发-高货翡翠原石尽在鑫劦飞翡翠年代翡翠原石集团
自己顶！！！！
学霸快粗来！！！
拿出数学课本后面的小题目，看一章写一章，看一章写一章。
高三？如果成绩并不好，你把课内的全做好就成了，一口吃不成胖子
谁知道网上哪儿能买到这东西 英语的
登录百度帐号推荐应用高中数学极限题,在线等_百度知道
色情、暴力
我们会通过消息、邮箱等方式尽快将举报结果通知您。
高中数学极限题,在线等
/zhidao/wh%3D600%2C800/sign=b6ec73ac0cbf5a3e8d109b3de9c82f9e5b0a06f18.jpg" esrc="http://a.hiphotos./zhidao/pic/item/de9c82f9e5b0a06f18解答过程如下：
采纳率：62%
来自团队：
45，则原式=lim(0-1)/(0+1)=-1若θ&45，则原式=lim(tan^n θ)&#47原式=lim (tan^n θ -1)/(tan^n θ +1)若θ=45 ，原式=0若θ&lt
若θ&45，则原式=lim(0-1)&#47;(0+1)=-1若θ&45，则原式=lim(tan^n θ)&#47;(tan^n θ)=1这个不懂，为什么小于45度就为0了？大于45度就这样了？
为您推荐：
其他类似问题
高中数学的相关知识
等待您来回答}